curl --request POST \
  --url https://api.iotools.cloud/v1/tool/power-factor-correction-calculator \
  --header 'Authorization: Bearer <token>' \
  --header 'Content-Type: application/json' \
  --data '
{
  "realPower": "100",
  "existingPf": "0.75",
  "targetPf": "0.95",
  "system": "three",
  "voltage": "400",
  "frequency": "50",
  "connection": "delta"
}
'

{
  "tool": "power-factor-correction-calculator",
  "tool_version": "1.0.1",
  "outputs": {
    "results": [
      {
        "quantity": "Power factor",
        "before": "0.75",
        "after": "0.95"
      },
      {
        "quantity": "Phase angle φ",
        "before": "41.4096°",
        "after": "18.1949°"
      },
      {
        "quantity": "Real power",
        "before": "100 kW",
        "after": "100 kW"
      },
      {
        "quantity": "Reactive power",
        "before": "88.1917 kvar",
        "after": "32.8684 kvar"
      },
      {
        "quantity": "Apparent power",
        "before": "133.333 kVA",
        "after": "105.263 kVA"
      },
      {
        "quantity": "Line current",
        "before": "192.45 A",
        "after": "151.934 A"
      }
    ],
    "capacitor": [
      {
        "item": "Required compensation",
        "value": "55.3233 kvar"
      },
      {
        "item": "kvar per kW (tan φ₁ − tan φ₂)",
        "value": "0.553233"
      },
      {
        "item": "Bank connection",
        "value": "Delta (3 capacitors)"
      },
      {
        "item": "Capacitor voltage",
        "value": "400 V"
      },
      {
        "item": "Capacitance per phase",
        "value": "366.874 µF"
      },
      {
        "item": "Total capacitance",
        "value": "1100.62 µF"
      },
      {
        "item": "Capacitor current per phase",
        "value": "46.1027 A"
      },
      {
        "item": "Capacitor line current",
        "value": "79.8523 A"
      },
      {
        "item": "Apparent power released",
        "value": "28.0702 kVA"
      },
      {
        "item": "Line current reduction",
        "value": "21.0526 %"
      }
    ],
    "breakdown": "φ₁ = acos(0.75) = 41.4096°   tan φ₁ = 0.881917\nφ₂ = acos(0.95) = 18.1949°   tan φ₂ = 0.328684\nQc = P × (tan φ₁ − tan φ₂) = 100 × 0.553233 = 55.3233 kvar\nS falls from 133.333 kVA to 105.263 kVA, freeing 28.0702 kVA\nI = S ÷ (√3 × 400 V): 192.45 A → 151.934 A\nC = (Qc ÷ 3) ÷ (2πf × 400²) = 366.874 µF per phase at 50 Hz\nPreliminary sizing only — harmonics, detuned reactors, switching steps and utility rules need an engineering review."
  },
  "credits_used": 3,
  "credits_remaining": null
}